pakai cara kalo bisa :)
Jawaban:
A. 2x(x³+2x+3)+(3x²+2)(x²+1)
Penjelasan dengan langkah-langkah:
f(x) = (x²+1)(x³+2x+3) => berbentuk u . v
u = x²+1 => u' = 2x
v = x³+2x+3 => v' = 3x²+2
f'(x) = u'v+uv'
= 2x(x³+2x+3)+(x²+1)(3x²+2)
= 2x(x³+2x+3)+(3x²+2)(x²+1) (A)
